Anti-Gravity Modulator

k*L=g*m

What if instead of matching the resonant mechanical frequency of the object, we match the resonant mechanical frequency of the earth and cancel out the gravitational vibration, changing the phase? Perhaps, would not that create a cancelling effect?

Now, on my hypothetical model, I regard gravitational forces as a frequency emanating from large objects such as planets or starts, which in turn resonate with smaller objects, attracting them. Thus, like the Boss headsets, we just cancel out the effect. It is the same principal as plugging bass woofers backwards, and cancelling the wave, so that there is no sound in between them.

So, we would want to cancel out the vibrational effect of gravity on an object by means of  placing a phase differential low frequency modulator bellow, or on top of the object we want to levitate.

These are the formulas to find the resonating frequency of the Earth in relation to the object.

f = {1\over 2 \pi} \sqrt {k\over m}

and

f = {1\over 2 \pi} \sqrt {g\over L}

where m is the mass and k is the spring constant.

where g is the acceleration due to gravity (about 9.8 m/s2 near the surface of Earth), and L is the length from the pivot point to the center of mass.(An elliptic integral yields a description for any displacement). Note that, in this approximation, the frequency does not depend on mass.

where k multiplied by L is equal to g multiplied by m.

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If successful, we can create a hover board, and build the pyramids again, and all sorts of Star Wars anti-gravity devices and vehicles.!!!

http://youtu.be/ouQcL2-L_kU

http://youtu.be/yd9DgsI95hc

http://en.wikipedia.org/wiki/Mechanical_resonance